JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
An object with mass 500 g moves along x -axis with speed \(v=4 \sqrt{x} \mathrm{~m} / \mathrm{s}\). The force acting on the object is :
- A 8 N
- B 5 N
- C 6 N
- D 4 N
Answer & Solution
Correct Answer
(D) 4 N
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & F=M \times a \\ & v=4 \sqrt{x} \\ & v^2=16 x \\ & 2 v \frac{d v}{d x}=16 \\ & \frac{v d v}{d x}=\frac{16}{2}=8 \\ & F=0.5 \times 8=4 N\end{aligned}\)
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