JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
Consider the following data :
Heat of formation of \(\mathrm{CO}_2(\mathrm{~g})=-393.5 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Heat of formation of \(\mathrm{H}_2 \mathrm{O}(\mathrm{l})=-286.0 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
Heat of combustion of benzene \(=-3267.0 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
The heat of formation of benzene is _ \(\mathrm{kJ} \mathrm{mol}{ }^{-1}\). (Nearest integer)
- A 46
- B 47
- C 48
- D 49
Answer & Solution
Correct Answer
(C) 48
Step-by-step Solution
Detailed explanation
\begin{aligned} & \Delta \mathrm{H}_{\mathrm{f}}\left[\mathrm{CO}_2(\mathrm{~g})\right]=-393.5 \mathrm{~kJ} / \mathrm{mole} \\ & \Delta \mathrm{H}_{\mathrm{f}}\left[\mathrm{H}_2 \mathrm{O}(\ell)\right]=-286.0 \mathrm{~kJ} / \mathrm{mole} \\ & \Delta…
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