ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2016
  • Medium
  • MCQ

In the following \('I'\) refers to current and other symbols have their usual meaning, Choose the option that corresponds to the dimensions of electrical conductivity

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(M^{-1}L^{-3}T^3I^2\)

Step-by-step Solution

Detailed explanation

We know that resistivity

\(\rho=\frac{R A}{\ell}\)

Conductivity \(=\frac{1}{\text { resistivity }}=\frac{\ell}{R A}\)

\(=\frac{\ell I}{V A}(\because V=R D)\)

\( = \frac{{[{\rm{L}}][{\rm{I}}]}}{{\left[ {\frac{{\left[ {{\rm{M}}{{\rm{L}}^2}{{\rm{T}}^{ - 2}}} \right]}}{{[I][{\rm{T}}]}}} \right] \times \left[ {{{\rm{L}}^2}} \right]}}\quad \left[ {{\rm{V}} = \frac{{\rm{W}}}{{\rm{q}}} = \frac{{\rm{W}}}{{{\rm{it}}}}} \right]\)

\(=\left[M^{-1} L^{-3} T^{3}\right]\left[I^{2}\right]=\left[M^{-1} L^{-3} T^{3} I^{2}\right]\)

Same subject
Explore more questions on app