JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
\(0.004\,M\,K _2 SO _4\) solution is isotonic with \(0.01\,M\) glucose solution. Percentage dissociation of \(K _2 SO _4\) is \(........\) (Nearest integer)
- A \(71\)
- B \(73\)
- C \(74\)
- D \(75\)
Answer & Solution
Correct Answer
(D) \(75\)
Step-by-step Solution
Detailed explanation
Isotonic solutions, \(\pi_{ K _2 SO _4}=\pi_{ Glucose }\) \(i \times 0.004 \times RT =0.01 \times RT\) \(i =2.5\) For \(K _2 SO _4 \quad\{\) for dissociation \(i =1+( n -1) \alpha\}\) \(\operatorname{DOD}(\alpha)=\frac{ i -1}{ n -1}=\frac{2.5-1}{3-1}=0.75\) \(\%\) dissociation…
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