JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
For water \(\Delta_{\text {vap }} \mathrm{H}=41 \mathrm{~kJ} \mathrm{~mol}^{-1}\) at \(373 \mathrm{~K}\) and 1 bar pressure. Assuming that water vapour is an ideal gas that occupies a much larger volume than liquid water, the internal energy change during evaporation of water is \(...... \mathrm{kJ}\, \mathrm{mol}^{-1}\) [Use: \(\left.\mathrm{R}=8.3 \,\mathrm{~J} \,\mathrm{~mol}^{-1}\, \mathrm{~K}^{-1}\right]\)
- A \(3.8\)
- B \(38\)
- C \(380\)
- D \(410\)
Answer & Solution
Correct Answer
(B) \(38\)
Step-by-step Solution
Detailed explanation
Given equation is \(\mathrm{H}_{2} \mathrm{O}(\ell) \longrightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{g}): \Delta \mathrm{H}=41\, \frac{\mathrm{kJ}}{\mathrm{mol}}\)…
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