JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
When ' \(\mathrm{x}\) ' \(\times 10^{-2} \mathrm{~mL}\) methanol (molar mass \(=32 \mathrm{~g}\); density \(=0.792 \mathrm{~g} / \mathrm{cm}^3\) ) is added to \(100 \mathrm{~mL}\) water (density \(=1 \mathrm{~g} / \mathrm{cm}^3\) ), the following diagram is obtained. (Image) \(x=\) _______ (nearest integer) [Given: Molal freezing point depression constant of water at \(273.15 \mathrm{~K}^2\) is \(1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\) ]

- A \(540\)
- B \(542\)
- C \(543\)
- D \(550\)
Answer & Solution
Correct Answer
(C) \(543\)
Step-by-step Solution
Detailed explanation
\(\Delta \mathrm{T}_{\mathrm{f}}=273.15-270.65=2.5 \mathrm{~K}\) \(\Delta \mathrm{T}_{\mathrm{f}}=\mathrm{K}_{\mathrm{f}} \mathrm{m} \Rightarrow 2.5=1.86 \times \frac{\mathrm{n}}{0.1}\) \(\Rightarrow \mathrm{n}=0.1344 \text { moles }\)…
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