JEE Advanced · Chemistry · 6. Thermodynamics (C)
The species which by definition has zero standard molar enthalpy of formation at \(298 \mathrm{~K}\) is
- A \(\mathrm{Br}_2(g)\)
- B \(\mathrm{Cl}_2(g)\)
- C \(\mathrm{H}_2 \mathrm{O}(g)\)
- D \(\mathrm{CH}_4(g)\)
Answer & Solution
Correct Answer
(B) \(\mathrm{Cl}_2(g)\)
Step-by-step Solution
Detailed explanation
\(\Delta H_f^{\circ}\left(\mathrm{Cl}_2, g\right)=0\)
\(\Delta H_f^{\circ}\) of elements in their standard state is taken to be zero. \(\mathrm{Cl}_2\) is gas, \(\mathrm{Br}_2\) is liquid and \(\mathrm{I}_2\) is solid at room temperature.
Energetics
Conceptual, implication of rules/laws III
\(\Delta H_f^{\circ}\) of elements in their standard state is taken to be zero. \(\mathrm{Cl}_2\) is gas, \(\mathrm{Br}_2\) is liquid and \(\mathrm{I}_2\) is solid at room temperature.
Energetics
Conceptual, implication of rules/laws III
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