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JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments

शीर्ष कोण \(\mathrm{A}\) के प्रिजम का अपवर्तनांक \(\cot \mathrm{A} / 2\) है। न्यूनतम विचलन कोण _______ हैं।

  1. A \(\delta_{\mathrm{m}}=180^{\circ}-\mathrm{A}\)
  2. B \(\delta_m=180^{\circ}-3 \mathrm{~A}\)
  3. C \(\delta_m=180^{\circ}-4 \mathrm{~A}\)
  4. D \(\delta_{\mathrm{m}}=180^{\circ}-2 \mathrm{~A}\)
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Answer & Solution

Correct Answer

(D) \(\delta_{\mathrm{m}}=180^{\circ}-2 \mathrm{~A}\)

Step-by-step Solution

Detailed explanation

\(\mu=\frac{\sin \left(\frac{A+\delta m}{2}\right)}{\sin \frac{A}{2}}\) \(\frac{\cos \frac{A}{2}}{\sin \frac{A}{2}}=\frac{\sin \left(\frac{A+\delta m}{2}\right)}{\sin \frac{A}{2}}\) \(\sin \left(\frac{\pi}{2}-\frac{A}{2}\right)=\sin \left(\frac{A+\delta_m}{2}\right)\)…
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