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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2024
  • Hard
  • MCQ

The refractive index of a prism with apex angle \(A\) is \(\cot A / 2\). The angle of minimum deviation is _______.

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Answer & Solution

Correct Answer

(D) \(\delta_{\mathrm{m}}=180^{\circ}-2 \mathrm{~A}\)

Step-by-step Solution

Detailed explanation

\(\mu=\frac{\sin \left(\frac{A+\delta m}{2}\right)}{\sin \frac{A}{2}}\)

\(\frac{\cos \frac{A}{2}}{\sin \frac{A}{2}}=\frac{\sin \left(\frac{A+\delta m}{2}\right)}{\sin \frac{A}{2}}\)

\(\sin \left(\frac{\pi}{2}-\frac{A}{2}\right)=\sin \left(\frac{A+\delta_m}{2}\right)\)

\(\frac{\pi}{2}-\frac{A}{2}=\frac{A}{2}+\frac{\delta m}{2}\)

\(\delta_m=\pi-2 A\)

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