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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter

एक इलेक्ट्रान, \(\alpha\)-कण एवं एक प्रोटॉन की गतिज ऊर्जा क्रमशः \(4 \mathrm{~K}, 2 \mathrm{~K}\) एवं \(\mathrm{K}\) है। इलेक्ट्रॉन, \(\alpha\)-कण तथा प्रोटॉन से सम्बन्धित डी-ब्रॉगली तरंगदैर्ध्य क्रमश: \(\lambda \mathrm{e}, \lambda \alpha\) तथा \(\lambda \mathrm{p}\) इस प्रकार हैं:

  1. A \(\lambda \alpha=\lambda p < \lambda e\)
  2. B \(\lambda \alpha > \lambda p > \lambda e\)
  3. C \(\lambda \alpha < \lambda p < \lambda e\)
  4. D \(\lambda \alpha=\lambda p>\lambda e\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\lambda \alpha < \lambda p < \lambda e\)

Step-by-step Solution

Detailed explanation

\(Electron\) \(Alpha\) \(Proton\) \(Mass:\) \(\frac{m}{1840}\) \(4m\) \(m\) \(Charge:\) \(e\) \(2e\) \(e\) \(Kinetic energy:\) \(4K\) \(2K\) \(K\) \(\lambda=\frac{h}{\sqrt{2 mK }}\) \(\frac{ h }{\sqrt{2 \cdot \frac{ m }{1840} \cdot 4 K }}\) \(\frac{h}{\sqrt{2.4 m.2K }}\)…
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