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JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement

द्रव्यमान \(m\) और ऊर्जा \(E\) वाले एक कण से संबंधित दे-ब्रॉगली तरंगदैर्ध्य \(\mathrm{h} / \sqrt{2 m E}\) है। प्लांक नियतांक का विमीय सूत्र _______ है।

  1. A \(\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]\)
  2. B \(\left[\mathrm{ML}^2 \mathrm{~T}^{-1}\right]\)
  3. C \(\left[\mathrm{MLT}^{-2}\right]\)
  4. D \(\left[\mathrm{M}^2 \mathrm{~L}^2 \mathrm{~T}^{-2}\right]\)
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Answer & Solution

Correct Answer

(B) \(\left[\mathrm{ML}^2 \mathrm{~T}^{-1}\right]\)

Step-by-step Solution

Detailed explanation

\(\lambda=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mE}}} \text { or } \mathrm{E}=\mathrm{h} \nu\) \({\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right]=\mathrm{h}\left[\mathrm{T}^{-1}\right]}\) \(\mathrm{h}=\left[\mathrm{ML}^2 \mathrm{~T}^{-1}\right]\)
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