ExamBro
ExamBro
JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion

द्रव्यमान \(m =2\) के एक कण की स्थिति, समय \(( t )\) के अनुसार \(\overrightarrow{ r }( t )=2 t \hat{ i }-3 t ^{2} \hat{ j }\) है। इस कण का मूलबिन्दु के सापेक्ष \(t =2\) पर कोणीय संवेग होगा।

  1. A \(-48\,\hat k\)
  2. B \(48\,(\hat i\, + \,\hat j)\)
  3. C \(36\,\hat k\)
  4. D \( - \,34\,(\hat k\, - \,\hat i)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(-48\,\hat k\)

Step-by-step Solution

Detailed explanation

\(\overrightarrow v = 2\hat i - 6 + \hat j\) \(At\,t = 2\) \(\overrightarrow v = 2\hat i - 12\hat j\) \(\overrightarrow p = m\overrightarrow v = 4i - 24\hat j\) \(At\,t = 2\) \(\overrightarrow r = 4\hat i - 12\hat j\)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app