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JEE Mains · Physics · STD 12 - 3. current electricity

चित्र में दिखाई गयी बैटरी से निकली धारा का मान (एम्पियर में) क्या होगा ? दिया गया है : \(R _{1}=15\, \Omega, R _{2}=10 \,\Omega, R _{3}=20\, \Omega, R _{4}=5\, \Omega\) \(R _{5}=25\, \Omega, R _{6}=30\, \Omega, E =15 \,V\)

  1. A \(13/24\)
  2. B \(7/18\)
  3. C \(9/32\)
  4. D \(20/3\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(9/32\)

Step-by-step Solution

Detailed explanation

\(R_{e q}=15+\frac{25}{3}+30=\frac{45+25+90}{3}=\frac{160}{3}\) \(\mathrm{I}=\frac{\mathrm{E}}{\mathrm{R}_{\mathrm{eq}}}=\frac{15 \times 3}{160}=\frac{9}{32} \,\mathrm{amp}\).
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