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JEE Mains · Maths · STD 11 - 10.1 circle and system of circle

यदि वृत्त \(x^2+y^2-10 x+4 y+13=0\) का एक व्यास दूसरे वृत्त \(\mathrm{C}\) की जीवा है, जिसका केन्द्र, रेखाओं \(2 x+3 y=12\) तथा \(3 x-2 y=5\) का प्रतिच्छेदन बिन्दु है, तो वृत्त \(\mathrm{C}\) की त्रिज्या ........... है।

  1. A \(\sqrt{20}\)
  2. B \(4\)
  3. C \(6\)
  4. D  \(3 \sqrt{2}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(6\)

Step-by-step Solution

Detailed explanation

\( 2 x+3 y=12 \) \(3 x-2 y=5\) \(13 x=39\) \(x=3, y=2\) Center of given circle is \((5,-2)\) \(\text { Radius } \sqrt{25+4-13}=4\) \(\therefore \mathrm{CM}=\sqrt{4+16}=5 \sqrt{2}\) \(\therefore \mathrm{CP}=\sqrt{16+20}=6\)
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