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JEE Mains · Maths · STD 12 - 8. Application and integration

वास्तविक संख्याओं \(a, b (a > b > 0)\) के लिये माना क्षेत्रफल है क्षेत्रफल \(\left\{(x, y): x^2+y^2 \leq a^2\right.\) तथा \(\left.\frac{x^2}{a^2}+\frac{y^2}{b^2} \geq 1\right\}=30 \pi\) तथा क्षेत्रफल \(\left\{(x, y): x^2+y^2 \geq b^2\right.\) तथा \(\left.\frac{x^2}{a^2}+\frac{y^2}{b^2} \leq 1\right\}=18 \pi\) है। तब \((a-b)^2\) का मान है

  1. A \(10\)
  2. B \(11\)
  3. C \(12\)
  4. D \(13\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(12\)

Step-by-step Solution

Detailed explanation

given \(\pi a ^{2}-\pi ab =30 \pi\) and \(\pi ab -\pi b ^{2}=18 \pi\) on subtracting, we get \((a-b)^{2}=a^{2}-2 a b+b^{2}=12\)
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