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JEE Mains · Maths · STD 12 - 8. Application and integration

For real numbers \(a, b (a> b >0)\), let Area \(\left\{(x, y): x^{2}+y^{2} \leq a^{2}\right.\) and \(\left.\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}} \geq 1\right\}=30 \pi\) and  Area \(\left\{(x, y): x^{2}+y^{2} \geq b^{2}\right.\) and \(\left.\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}} \leq 1\right\}=18 \pi\)  Then the value of \((a-b)^{2}\) is equal to

  1. A \(10\)
  2. B \(11\)
  3. C \(12\)
  4. D \(13\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(12\)

Step-by-step Solution

Detailed explanation

given \(\pi a ^{2}-\pi ab =30 \pi\) and \(\pi ab -\pi b ^{2}=18 \pi\) on subtracting, we get \((a-b)^{2}=a^{2}-2 a b+b^{2}=12\)