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JEE Mains · Maths · STD 12 - 10. vector algebra

माना तीन बिन्दु \(A , B , C\) है जिसके स्थिति सदिश क्रमश: \(\vec{a}=\hat{i}+4 \hat{j}+3 \hat{k}\) \(\vec{b}=2 \hat{i}+\alpha \hat{j}+4 \hat{k}, \alpha \in R\) \(\vec{c}=3 \hat{i}-2 \hat{j}+5 \hat{k}\) है। यदि न्यूनतम धनात्मक पूर्णांक \(\alpha\) जिसके लिये \(\vec{a}, \vec{b}, \vec{c}\) असमरेखीय है तो \(\triangle ABC\) में माध्यिका की लम्बाई, जो \(A\) से गुजरती है, होगी

  1. A \(\frac{\sqrt{82}}{2}\)
  2. B \(\frac{\sqrt{62}}{2}\)
  3. C \(\frac{\sqrt{69}}{2}\)
  4. D \(\frac{\sqrt{66}}{2}\)
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Answer & Solution

Correct Answer

(A) \(\frac{\sqrt{82}}{2}\)

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Detailed explanation

\(\overline{ AB } \| \overline{ AC }\) if \(\frac{1}{2}=\frac{\alpha-4}{-6}=\frac{1}{2} \Rightarrow \alpha=1\) \(\vec{a}, \vec{b}, \vec{c}\) are non-collinear for \(\alpha=2\) (smallest positive integer) Mid-point of \(BC = M \left(\frac{5}{2}, 0, \frac{9}{2}\right)\)…
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