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JEE Mains · Maths · STD 12 - 11. three dimension geometry

माना दिक् अनुपात \(1,-4,2\) रखने वाली एक रेखा, रेखाओं \(\frac{ x -7}{3}=\frac{ y -1}{-1}=\frac{ z +2}{1} \quad\) तथा \(\frac{ x }{2}=\frac{ y -7}{3}=\frac{ z }{1}\) को बिन्दु \(A\) तथा \(B\) पर काटती है। तब \(( AB )^2\) बराबर है

  1. A \(85\)
  2. B \(98\)
  3. C \(78\)
  4. D \(84\)
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Answer & Solution

Correct Answer

(D) \(84\)

Step-by-step Solution

Detailed explanation

DR's of \(A B\) \((3 \lambda-2 \mu+7,-\lambda-3 \mu-6, \lambda-\mu-2)\) \(\frac{3 \lambda-2 \mu+7}{1}=\frac{-\lambda-3 \mu-6}{-4}=\frac{\lambda-\mu-2}{2}\) Taking first (\(2\)) \(-12 \lambda+8 \mu-28=-\lambda-3 \mu-6\) \(\lambda-\mu+2=0\) Taking second and third…
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