JEE Mains · Maths · STD 12 - 11. three dimension geometry
Let a line having direction ratios \(1,-4,2\) intersect the lines \(\frac{x-7}{3}=\frac{y-1}{-1}=\frac{z+2}{1}\) and \(\frac{x}{2}=\frac{y-7}{3}=\frac{z}{1}\) at the point \(A\) and \(B\). Then \(( AB )^{2}\) is equal to
- A \(85\)
- B \(98\)
- C \(78\)
- D \(84\)
Answer & Solution
Correct Answer
(D) \(84\)
Step-by-step Solution
Detailed explanation
DR's of \(A B\) \((3 \lambda-2 \mu+7,-\lambda-3 \mu-6, \lambda-\mu-2)\) \(\frac{3 \lambda-2 \mu+7}{1}=\frac{-\lambda-3 \mu-6}{-4}=\frac{\lambda-\mu-2}{2}\) Taking first (\(2\)) \(-12 \lambda+8 \mu-28=-\lambda-3 \mu-6\) \(\lambda-\mu+2=0\) Taking second and third…
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