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JEE Mains · Maths · STD 12 - 9. differential equations

माना अवकल समीकरण \(\left(x-x^{3}\right) d y=\left(y+y x^{2}-3 x^{4}\right) d x\), \(x >2\) का हल \(y = y ( x )\) है। यदि \(y =3\) है, तो \(y\) बराबर है

  1. A \(1\)
  2. B \(2\)
  3. C \(3\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

\(\sec y \frac{d y}{d x}=2 \sin x \cos y\) \(\sec ^{2} y d y=2 \sin x d x\) \(\tan y=-2 \cos x+c\) \(c=2\) \(\tan y=-2 \cos x+2 \Rightarrow \text { at } x=\frac{\pi}{2}\) \(\tan y=2\) \(\sec ^{2} y \frac{d y}{d x}=2 \sin x\) \(5 \frac{d y}{d x}=2\)
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