ExamBro
ExamBro
JEE Mains · Maths · STD 12 - 11. three dimension geometry

यदि \(\frac{x+\sqrt{6}}{2}=\frac{y-\sqrt{6}}{3}=\frac{z-\sqrt{6}}{4}\) और \(\frac{x-\lambda}{3}=\frac{y-2 \sqrt{6}}{4}=\frac{z+2 \sqrt{6}}{5}\) के बीच न्यूनतम दूरी \(6\) है, तब \(\lambda\) के सभी संभव मानो के योग का वर्ग है________. 

  1. A \(380\)
  2. B \(3885\)
  3. C \(386\)
  4. D \(384\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(384\)

Step-by-step Solution

Detailed explanation

Shortest distance between the lines \(\frac{x+\sqrt{6}}{2}=\frac{y-\sqrt{6}}{3}=\frac{z-\sqrt{6}}{4}\) \(\frac{x-\lambda}{3}=\frac{y-2 \sqrt{6}}{4}=\frac{2+2 \sqrt{6}}{5}\) is \(6\) Vector along line of shortest distance…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app