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JEE Mains · Maths · STD 11 - 4.1 complex nubers

माना \(a, b \in \mathbb{C}\) हैं। माना \(\alpha, \beta\) समीकरण \(x^2 + ax + b = 0\) के मूल हैं। यदि \(\beta - \alpha = \sqrt{11}\) और \(\beta^2 - \alpha^2 = 3i\sqrt{11}\) है, तो \((\beta^3 - \alpha^3)^2\) किसके बराबर है:

  1. A \(160\)
  2. B \(176\)
  3. C \(194\)
  4. D \(187\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(176\)

Step-by-step Solution

Detailed explanation

दिया गया है \(\beta - \alpha = \sqrt{11}\) और \(\beta^2 - \alpha^2 = 3i\sqrt{11}\) \(\beta + \alpha = \dfrac{\beta^2 - \alpha^2}{\beta - \alpha} = \dfrac{3i\sqrt{11}}{\sqrt{11}} = 3i\) सर्वसमिका \((\beta - \alpha)^2 = (\beta + \alpha)^2 - 4\alpha\beta\) का उपयोग करने पर…
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