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JEE Mains · Physics · STD 12 - 8. Electromagnetic waves

\(+x\) દિશામાં ગતિ કરતાં વિદ્યુતચુંબકીય તરંગ માટે આવૃતિ \(2 \times 10^{14}\,Hz\) અને વિદ્યુતક્ષેત્રનું મૂલ્ય \(27\,Vm^{-1}\) છે. આ તરંગ માટે આપેલ ચાર વિકલ્પ પૈકી કોણ ચુંબકીયક્ષેત્રને સાચી રીતે દર્શાવે છે?

  1. A \(\vec B\,(x\,,\,t) = (3 \times {10^{ - 8}}\,T)\,\hat j \;\sin \,[2\pi \,(1.5 \times {10^{ - 8}}\,x\, - \,2 \times {10^{14}}\,t)]\)
  2. B \(\vec B\,(x\,,\,t) = (9 \times {10^{ - 8}}\,T)\,\hat i\; \sin \,[2\pi \,(1.5 \times {10^{ - 8}}\,x\, - \,2 \times {10^{14}}\,t)]\)
  3. C \(\vec B\,(x\,,\,t) = (9 \times {10^{ - 8}}\,T)\,\hat j\;\sin \,[(1.5 \times {10^{ - 6}}\,x\, - \,2 \times {10^{14}}\,t)]\)
  4. D \(\vec B\,(x\,,\,t) = (9 \times {10^{ - 8}}\,T)\,\hat k \;\sin \,[2\pi \,(1.5 \times {10^{ - 6}}\,x\, - \,2 \times {10^{14}}\,t)]\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\vec B\,(x\,,\,t) = (9 \times {10^{ - 8}}\,T)\,\hat k \;\sin \,[2\pi \,(1.5 \times {10^{ - 6}}\,x\, - \,2 \times {10^{14}}\,t)]\)

Step-by-step Solution

Detailed explanation

As we know, \(B_{0}=\frac{E_{0}}{C}=\frac{27}{3 \times 10^{8}}=9 \times 10^{-8}\) \(tesla\) Oscillation of \(B\) can be only along \(\hat{\jmath}\) or \(\hat{k}\) direction. \(\omega=2 \pi f=2 \pi \times 2 \times 10^{14} \,\mathrm{Hz}\)…
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