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JEE Mains · Maths · STD 12 - 6. Application of derivatives

\(\max_{0 \leq x \leq \pi}\left(16\sin\left(\dfrac{x}{2}\right)\cos^3\left(\dfrac{x}{2}\right)\right)\) બરાબર છે:

  1. A \(\dfrac{3\sqrt{3}}{2}\)
  2. B \(3\sqrt{3}\)
  3. C \(4\sqrt{3}\)
  4. D \(6\sqrt{3}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(3\sqrt{3}\)

Step-by-step Solution

Detailed explanation

ધારો કે \(y = \dfrac{x}{2}\). કારણ કે \(0 \leq x \leq \pi\), આપણને \(0 \leq y \leq \dfrac{\pi}{2}\) મળે છે. આપેલ પદાવલિ \(f(y) = 16\sin y \cos^3 y\) બને છે. \(y\) ની સાપેક્ષે વિકલન કરતા: \(f'(y) = 16(\cos y \cdot \cos^3 y + \sin y \cdot 3\cos^2 y(-\sin y))\)…
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