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JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases

સમોષ્મિ પ્રક્રિયા દરમિયાન આદર્શ વાયુનું કદ બમણું થાય છે. બે વાયુના અણું વચ્ચેનો સરેરાશ અથડામણ સમય \(\tau_{1}\) થી \(\tau_{2}\) થાય છે. જો \(\frac{C_{p}}{C_{v}}=\gamma\) હોય તો આ વાયુ માટે \(\frac{\tau_{2}}{\tau_{1}}\) કેટલો થશે?

  1. A \(\left(\frac{1}{2}\right)^{\frac{\gamma+1}{2}}\)
  2. B \(2\)
  3. C \(\frac 12\)
  4. D \(\left(\frac{1}{2}\right)^{\gamma}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\left(\frac{1}{2}\right)^{\frac{\gamma+1}{2}}\)

Step-by-step Solution

Detailed explanation

\({\lambda \propto V}\) The average time between the collisions of the gas molecules is nothing but the mean free path divided by the root mean square speed of the gas molecules. \(\mathrm{So}\) \(\Longrightarrow\left[\text { Time }=t=\frac{\lambda}{v_{R M S}}\right]\) Now we…
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