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JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement

બે અવરોધો \({R}_{1}=(4 \pm 0.8)\; \Omega\) અને \({R}_{2}=(4 \pm 0.4)\;\Omega\) ને સમાંતરમાં જોડેલ છે. સમાંતરનો સમતુલ્ય અવરોધ કેટલો થાય?

  1. A \((4 \pm 0.4)\, \Omega\)
  2. B \((2 \pm 0.4)\, \Omega\)
  3. C \((2 \pm 0.3) \,\Omega\)
  4. D \((4 \pm 0.3) \,\Omega\)
Verified Solution

Answer & Solution

Correct Answer

(C) \((2 \pm 0.3) \,\Omega\)

Step-by-step Solution

Detailed explanation

\(\frac{1}{{R}_{{eq}}}=\frac{1}{{R}_{1}}+\frac{1}{{R}_{2}}\) \(\frac{1}{{R}_{{eq}}}=\frac{1}{4}+\frac{1}{4} \Rightarrow {R}_{{eq}}=2\, \Omega\) Also \(\frac{\Delta {R}_{{eq}}}{{R}_{{eq}}^{2}}=\frac{\Delta {R}_{1}}{{R}_{1}^{2}}+\frac{\Delta {R}_{2}}{{R}_{2}^{2}}\)…
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