આકૃત્તિમાં દર્શાવ્યા મુજબ, માધ્યમ \(1\) માંથી પસાર થયા બાદ માધ્યમ \(2\) માં પ્રકાશની ઝડ૫ વેગ \(v_{2} \ldots\) \(\times 10^{8}\,ms ^{-1}\) થશે. ( \(c =3 \times 10^{8} \,ms ^{-1}\) આપેલ છે.)

A \(1.0\)
B \(0.5\)
C \(1.5\)
D \(3.0\)

Verified Solution

Answer & Solution

Correct Answer

(A) \(1.0\)

Step-by-step Solution

Detailed explanation

\(\frac{\mu_{2}}{\mu_{ air }}=\frac{ C }{ V _{2}}\) \(\therefore \frac{\sqrt{\mu_{ r _{2}} \varepsilon_{ r _{2}}}}{(1)}=\frac{ C }{ V _{2}}\) \(\therefore \sqrt{(1)(9)}=\frac{C}{v_{2}}\) \(\therefore v _{2}=\frac{ C }{3}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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\(\tan \left(2 \tan ^{-1} \frac{1}{5}+\sec ^{-1} \frac{\sqrt{5}}{2}+2 \tan ^{-1} \frac{1}{8}\right)\) ની કિમંત મેળવો.

JEE Mains 2022 Easy

લિસ્ટ \(-I\) ને લિસ્ટ \(-II\) સાથે સરખાવો

લિસ્ટ \(-I\)	લિસ્ટ \(-II\)
\((a)\) કેપેસીટન્સ, \(C\)	\((i)\) \({M}^{1} {L}^{1} {T}^{-3} {A}^{-1}\)
\((b)\) શૂન્યાવકાશની પરમિટિવિટી, \(\varepsilon_{0}\)	\((ii)\) \({M}^{-1} {L}^{-3} {T}^{4} {A}^{2}\)
\((c)\) શૂન્યાવકાશની પરમીબીલીટી, \(\mu_{0}\)	\((iii)\) \({M}^{-1} L^{-2} T^{4} A^{2}\)
\((d)\) વિદ્યુતક્ષેત્ર, \(E\)	\((iv)\) \({M}^{1} {L}^{1} {T}^{-2} {A}^{-2}\)

આપેલ વિકલ્પો માંથી સાચો વિકલ્પ પસંદ કરો.

JEE Mains 2021 Medium

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