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JEE Mains · Maths · STD 12 - 8. Application and integration

વક્ર \(y=\log _{ t }\left( x + e ^{2}\right)\), \(x=\log _{ e }\left(\frac{2}{ y }\right)\) અને \(x =\log _{ e } 2\), દ્વારા \(y =1\) ની ઉપરની બાજુએ આવૃત પ્રદેશનું ક્ષેત્રફળ મેળવો.

  1. A \(2+e-\log _{e} 2\)
  2. B \(1+e-\log _{e} 2\)
  3. C \(e -\log _{ e } 2\)
  4. D \(1+\log _{ e } 2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1+e-\log _{e} 2\)

Step-by-step Solution

Detailed explanation

Required area is \(=\int_{0-0^{2}}^{0} \ln \left( x + e ^{2}\right)-1 dx +\int_{0}^{\ln 2} 2 e ^{- x }-1 dx =1+ e -\operatorname{\ell n} 2\)
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