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JEE Mains · Maths · STD 11 - 7. binomial theoram

\(19^{200}+23^{200}\) ને \(49\) વડે ભાગતા શેષ કેટલી મળે.

  1. A \(28\)
  2. B \(27\)
  3. C \(29\)
  4. D \(26\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(29\)

Step-by-step Solution

Detailed explanation

\((21+2)^{200}+(21-2)^{200}\) \(\Rightarrow 2\left[{ }^{100} C _0 21^{200}+200 C _2 21^{198} \cdot 2^2+\ldots . .+{ }^{200} C _{198} 21^2\right.\) \(\left.2^{198}+2^{200}\right]\) \(\Rightarrow 2\left[49 I _1+2^{200}\right]=49 I _1+2^{201}\) Now,…
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