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JEE Mains · Maths · STD 11 - 7. binomial theoram

\(\left\{7^{\left(\frac{1}{2}\right)}+11\left(\frac{1}{6}\right)\right\}^{824}\) નાં વિસ્તરણમાં પૂર્ણાંક પદોની સંખ્યા ........... છે.

  1. A \(142\)
  2. B \(138\)
  3. C \(421\)
  4. D \(456\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(138\)

Step-by-step Solution

Detailed explanation

General term in expansion of \(\left((7)^{1 / 2}+(11)^{1 / 6}\right)^{824}\) is \(t_{I+1}={ }^{824} C_{\mathrm{r}}(7)^{\frac{824-\mathrm{I}}{2}}(11)^{\mathrm{I} / 6}\) For integral term, \(r\) must be multiple of \(6\) . Hence \(r=0,6,12, \ldots \ldots \ldots........ .822\)
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