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JEE Mains · Maths · STD 12 - 8. Application and integration

વક્ર \(x^2 = 4y\) અને રેખા \(x = 4y - 2\) દ્વારા  આવૃત પ્રદેશ નું ક્ષેત્રફળ મેળવો .

  1. A \(5/4\)
  2. B \(9/8\)
  3. C \(7/8\)
  4. D \(3/4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(9/8\)

Step-by-step Solution

Detailed explanation

\(x^{2}=4 y\) \(. . . .(1)\) \(x+2=4 y\) .......\((2)\) Solve \(( 1)\) and \(( 2)\) \(x+2=x^{2}\) \(\Rightarrow x^{2}-x-2=0\) \(\Rightarrow(x-2)(x+1)=0 \) \(\Rightarrow x=2,-1\) Area \( = \int\limits_{ - 1}^2 {\left( {\frac{{x + 2}}{4} - \frac{{{x^2}}}{4}} \right)dx} \)…
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