JEE Mains · Maths · STD 12 - 8. Application and integration
The area (in sq. units) of the region bounded by the curve \(x^2 = 4y\) and the straight line \(x = 4y - 2\) is
- A \(5/4\)
- B \(9/8\)
- C \(7/8\)
- D \(3/4\)
Answer & Solution
Correct Answer
(B) \(9/8\)
Step-by-step Solution
Detailed explanation
\(x^{2}=4 y\) \(. . . .(1)\) \(x+2=4 y\) .......\((2)\) Solve \(( 1)\) and \(( 2)\) \(x+2=x^{2}\) \(\Rightarrow x^{2}-x-2=0\) \(\Rightarrow(x-2)(x+1)=0 \) \(\Rightarrow x=2,-1\) Area \( = \int\limits_{ - 1}^2 {\left( {\frac{{x + 2}}{4} - \frac{{{x^2}}}{4}} \right)dx} \)…
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