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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

વિકલનીય વિધેય \(f:(0, \infty) \rightarrow R\) માટે ધારો કે \(f(x)-f(y) \geqslant \log _{\mathrm{e}}\left(\frac{x}{y}\right)+x-y, \forall x, y \in(0, \infty)\). તો \(\sum_{\mathrm{n}=1}^{20} f^{\prime}\left(\frac{1}{\mathrm{n}^2}\right)\) \(=\) ...........

  1. A \(8569\)
  2. B \(2890\)
  3. C \(1256\)
  4. D \(3564\)
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Answer & Solution

Correct Answer

(B) \(2890\)

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Detailed explanation

\( f(x)-f(y) \geq \ln x-\ln y+x-y \) \( \frac{f(x)-f(y)}{x-y} \geq \frac{\ln x-\ln y}{x-y}+1 \) Let \(x>y \) \(\lim _{y \rightarrow x} f^{\prime}\left(x^{-}\right) \geq \frac{1}{x}+1 \quad \ldots\) \( ........(1) \) Let \(x>y\)…
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