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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

ધારો કે  વિધેય \(f\) એ  \([\mathrm{a}, \mathrm{b}]\) પર સતત અને \((a, b) \) પર દ્રીતીય વિકલનીય છે. જો દરેક \(x \in(a, b)\) ; \(f^{\prime}(\mathrm{x})>0\) અને  \(f^{\prime \prime}(\mathrm{x})<0,\) હોય તો કોઈક  \(\mathrm{c} \in(\mathrm{a}, \mathrm{b})\) ;  \(\frac{f(\mathrm{c})-f(\mathrm{a})}{f(\mathrm{b})-f(\mathrm{c})}\)  \(>\) 

  1. A \(\frac{b+a}{b-a}\)
  2. B \(\frac{b-c}{c-a}\)
  3. C \(\frac{c-a}{b-c}\)
  4. D \(1\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{c-a}{b-c}\)

Step-by-step Solution

Detailed explanation

it is clear from graph that \(\mathrm{m}_{1}>\mathrm{m}_{2}\) \(\Rightarrow \quad \frac{f(\mathrm{c})-f(\mathrm{a})}{\mathrm{c}-\mathrm{a}}>\frac{f(\mathrm{b})-f(\mathrm{c})}{\mathrm{b}-\mathrm{c}}\) \(\Rightarrow \quad \frac{f(c)-f(a)}{f(b)-f(c)}>\frac{c-a}{b-c}\)
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