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JEE Mains · Maths · STD 11 - 12. limits

[t] એ t થી નાનો અથવા t ની બરાબર હોય તેવો સૌથી મોટો પૂર્ણાંક છે. તો \(\mathrm{p} \in \mathbf{N}\) નું ન્યૂનતમ મૂલ્ય જેના માટે \(\lim _{x \rightarrow 0^{+}}(x\left(\left[\frac{1}{x}\right]+\left[\frac{2}{x}\right]+\ldots+\left[\frac{\mathrm{p}}{x}\right]\right)-x^2(\left[\frac{1}{x^2}\right]+\left[\frac{2^2}{x^2}\right]\) \(+\ldots+\left[\frac{9^2}{x^2}\right])) \geq 1\) છે, તે ________ છે.

  1. A 21
  2. B 22
  3. C 23
  4. D 24
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Answer & Solution

Correct Answer

(D) 24

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Detailed explanation

\(\lim _{x \rightarrow 0^{+}}(x\left(\left[\frac{1}{x}\right]+\left[\frac{2}{x}\right]+\ldots . .+\left[\frac{p}{x}\right]\right)-x^2(\left[\frac{1}{x^2}\right]+\) \(\left[\frac{2^2}{x^2}\right]+\left[\frac{9^2}{x^2}\right])) \geq 1 \)…
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