JEE Mains · Maths · STD 11 - 12. limits
Let [t] be the greatest integer less than or equal to t. Then the least value of \(\mathrm{p} \in \mathbf{N}\) for which \(\lim _{x \rightarrow 0^{+}}(x\left(\left[\frac{1}{x}\right]+\left[\frac{2}{x}\right]+\ldots+\left[\frac{\mathrm{p}}{x}\right]\right)-x^2(\left[\frac{1}{x^2}\right]+\left[\frac{2^2}{x^2}\right]\) \(+\ldots+\left[\frac{9^2}{x^2}\right])) \geq 1\) is equal to ________.
- A 21
- B 22
- C 23
- D 24
Answer & Solution
Correct Answer
(D) 24
Step-by-step Solution
Detailed explanation
\(\lim _{x \rightarrow 0^{+}}(x\left(\left[\frac{1}{x}\right]+\left[\frac{2}{x}\right]+\ldots . .+\left[\frac{p}{x}\right]\right)-x^2(\left[\frac{1}{x^2}\right]+\) \(\left[\frac{2^2}{x^2}\right]+\left[\frac{9^2}{x^2}\right])) \geq 1 \)…
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