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JEE Mains · Maths · STD 12 - 7.2 definite integral

સંકલન \(\displaystyle\int_0^\infty \dfrac{\log_e(x)}{x^2 + 4}\,dx\) નું મૂલ્ય છે:

  1. A \(\dfrac{\pi\log_e(2)}{2}\)
  2. B \(\dfrac{\pi\log_e(2)}{4}\)
  3. C \(1 + \pi\log_e(2)\)
  4. D \(2 + \pi\log_e(2)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\dfrac{\pi\log_e(2)}{4}\)

Step-by-step Solution

Detailed explanation

ધારો કે \(I = \displaystyle\int_0^\infty \dfrac{\log_e(x)}{x^2 + 4}\,dx\) આદેશ \(x = 2 \tan \theta\) લેતા, જેથી \(dx = 2 \sec^2 \theta \,d\theta\) મળે. સંકલનની સીમાઓ \(x = 0 \) થી \( \theta = 0\) અને \(x \to \infty \) થી \( \theta = \dfrac{\pi}{2}\) માં ફેરવાય છે.…
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