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JEE Mains · Maths · STD 12 - 11. three dimension geometry

સમતલો  \(2x - y - 4 = 0\) અને  \(y + 2z - 4 = 0\) ની છેદરેખામાંથી પસાર થતાં અને બિંદુ \((1, 1, 0)\) માંથી પસાર થતાં સમતલનું સમીકરણ મેળવો.

  1. A \(x + 3y + z = 4\)
  2. B \(2x - z = 2\)
  3. C \(x - 3y - 2z = -2\)
  4. D \(x - y - z = 0\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(x - y - z = 0\)

Step-by-step Solution

Detailed explanation

The required plane is \((2 x-y-4)+\lambda(y+2 z-4)=0\) it passes through \((1,1,0)\) \(\Rightarrow(2-1-4)+\lambda(1-4)=0\) \(\Rightarrow-3-3 \lambda=0 \Rightarrow \lambda=-1\) \(\Rightarrow x-y-z=0\)
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