ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 11 - 4.1 complex nubers

સમીકરણ \(x^{3}-2 x^{2}+2 x-1=0\) નાં બીજોની \(162\) મી ઘાતનો સરવાળો ......... થાય.

  1. A \(2\)
  2. B \(9\)
  3. C \(3\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(3\)

Step-by-step Solution

Detailed explanation

\(x^{3}-2 x^{2}+2 x-1=0\) \(x =1\) satisfying the equation \(\therefore x-1\) is factor of \(x^{3}-2 x^{2}+2 x-1\) \(=(x-1)\left(x^{2}-x+1\right)=0\) \(x=1, \frac{1+i \sqrt{3}}{2}, \frac{1-i \sqrt{3}}{2}\) \(x=1,-\omega^{2},-\omega\) sum of \(162^{\text {th }}\) power of roots…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app