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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant

જો સમીકરણો  \(2x + 3y - z = 0\), \(x + ky - 2z = 0\) અને  \(2x - y + z = 0\) ને શૂન્યતર ઉકેલ \((x, y, z)\) હોય તો  \(\frac{x}{y} + \frac{y}{z} + \frac{z}{x} + k\) મેળવો.

  1. A \(\frac{3}{4}\)
  2. B \(-4\)
  3. C \(\frac{1}{2}\)
  4. D \(-\frac{1}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{1}{2}\)

Step-by-step Solution

Detailed explanation

system of equations has non trival solution \(\therefore D = 0 = \left| {\begin{array}{*{20}{c}} 2&3&{ - 1}\\ 1&k&{ - 2}\\ 2&{ - 1}&1 \end{array}} \right| = 0\) \( \Rightarrow k = \frac{9}{2}\) So equation are \(2x + 3y - z = 0\,\,\,\,\,\,\,\,\,.....\left( 1 \right)\)…
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