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JEE Mains · Maths · STD 11 - 8. sequence and series

શ્રેણી \(20,19 \frac{1}{4}, 18 \frac{1}{2}, 17 \frac{3}{4}, \ldots,-129 \frac{1}{4}\) ના છેડાથી \(20^{\text {th}}\) પદ ........... છે.

  1. A \(-118\)
  2. B \(-110\)
  3. C \(-115\)
  4. D \(-100\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(-115\)

Step-by-step Solution

Detailed explanation

\(20,19 \frac{1}{4}, 18 \frac{1}{2}, 17 \frac{3}{4}, \ldots \ldots,-129 \frac{1}{4}\) This is \(A.P\). with common difference \( d_1=-1+\frac{1}{4}=-\frac{3}{4} \) \( -129 \frac{1}{4}, \ldots \ldots \ldots . . ., 19 \frac{1}{4}, 20\) This is also \(A.P.\) \(a=-129 \frac{1}{4}\)…
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