JEE Mains · Maths · STD 12 - 11. three dimension geometry
If the angle between the line \(2(x + 1)\,= y\, = z + 4\) and the plane \(2x -\sqrt \lambda \,z+4\,=0\) is \(\frac{\pi}{6}\), then the value of \(\lambda \), is
- A \(\frac{135}{7}\)
- B \(\frac{45}{11}\)
- C \(\frac{45}{7}\)
- D \(\frac{135}{11}\)
Answer & Solution
Correct Answer
(C) \(\frac{45}{7}\)
Step-by-step Solution
Detailed explanation
Given equation of line can be written as \(\frac{x+1}{1}=\frac{y}{2}=\frac{z+4}{2}\) Eqn of plane is \(2 x-y+\sqrt{\lambda} z+4=0\) Since, angle between the line and the plane is \(\frac{\pi}{6}\) therefore…
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