ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 11 - 7. binomial theoram

 જો  \((\mathrm{x}+3)^{\mathrm{n}-1}+(\mathrm{x}+3)^{\mathrm{n}-2}(\mathrm{x}+2)+ \) \( (\mathrm{x}+3)^{\mathrm{n}-3}(\mathrm{x}+2)^2+\ldots . .+(\mathrm{x}+2)^{\mathrm{n}-1}\) માં \(x^r\) નો સહગુણક \(\alpha_{\mathrm{r}}\) છે. જો \(\sum_{\mathrm{r}-0}^{\mathrm{n}} \alpha_{\mathrm{r}}=\beta^{\mathrm{n}}-\gamma^{\mathrm{n}}, \beta, \gamma \in \mathrm{N}\), તો \(\beta^2+\gamma^2=\) ...........

  1. A \(23\)
  2. B \(24\)
  3. C \(20\)
  4. D \(25\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(25\)

Step-by-step Solution

Detailed explanation

\((x+3)^{n-1}+(x+3)^{n-2}(x+2)+(x+3)^{n-3} \) \( (x+2)^2+\ldots \ldots . .+(x+2)^{n-1} \) \(\sum \alpha_r=4^{n-1}+4^{n-2} \times 3+4^{n-3} \times 3^2 \ldots \ldots+3^{n-1} \)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app