JEE Mains · Maths · STD 11 - 7. binomial theoram
Let the coefficient of \(x^{\mathrm{r}}\) in the expansion of \((\mathrm{x}+3)^{\mathrm{n}-1}+(\mathrm{x}+3)^{\mathrm{n}-2}(\mathrm{x}+2)+\) \((\mathrm{x}+3)^{\mathrm{n}-3}(\mathrm{x}+2)^2+\ldots \ldots+(\mathrm{x}+2)^{\mathrm{n}-1}\) be \(\alpha_{\mathrm{r}}\). If \(\sum_{\mathrm{r}=0}^{\mathrm{n}} \alpha_{\mathrm{r}}=\beta^{\mathrm{n}}-\gamma^{\mathrm{n}}, \beta, \gamma \in \mathrm{N}\), then the value of \(\beta^2+\gamma^2\) equals ...........
- A \(23\)
- B \(24\)
- C \(20\)
- D \(25\)
Answer & Solution
Correct Answer
(D) \(25\)
Step-by-step Solution
Detailed explanation
\((x+3)^{n-1}+(x+3)^{n-2}(x+2)+(x+3)^{n-3} \) \( (x+2)^2+\ldots \ldots . .+(x+2)^{n-1} \) \(\sum \alpha_r=4^{n-1}+4^{n-2} \times 3+4^{n-3} \times 3^2 \ldots \ldots+3^{n-1} \)…
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