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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

જો \(2\) અને \(6\) એ સમીકરણ \(\mathrm{a} x^2+\mathrm{b} x+1=0\) ના બીજ હોય, તો જેના બીજ \(\frac{1}{2 \mathrm{a}+\mathrm{b}}\) તથા \(\frac{1}{6 \mathrm{a}+\mathrm{b}}\), હોય, તેવું દ્રીધાત સમીક૨ણ .......... છે.

  1. A \(2 x^2+11 x+12=0\)
  2. B \(4 x^2+14 x+12=0\)
  3. C \(x^2+10 x+16=0\)
  4. D \(x^2+8 x+12=0\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(x^2+8 x+12=0\)

Step-by-step Solution

Detailed explanation

Sum \(=8=-\frac{b}{a} \) Product \(=12=\frac{1}{a} \quad \Rightarrow a=\frac{1}{12} \) \( b=-\frac{2}{3} \) \( 2 a+b=\frac{2}{12}-\frac{2}{3}=-\frac{1}{2} \) \( 6 a+b=\frac{6}{12}-\frac{2}{3}=-\frac{1}{6} \) sum \(=-8 \) \( P=12 \) \( x^2+8 x+12=0\)
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