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JEE Mains · Maths · STD 12 - 10. vector algebra

જો સ્થાન સદિશો \(\vec{a}, \vec{b}, \vec{c}\) અને \(\vec{d}\) વાળા ચાર ભિન્ન બિંદુુઓ સમતલીય હોય, તો \([\vec{a} \vec{b} \vec{c}]=........\)

  1. A \([\overrightarrow{ d } \overrightarrow{ c } \overrightarrow{ a }]+[\overrightarrow{ b } \overrightarrow{ d } \overrightarrow{ a }]+[\overrightarrow{ c } \overrightarrow{ d } \overrightarrow{ b }]\)
  2. B \([\overrightarrow{ d } \overrightarrow{ b } \overrightarrow{ d }]+[\overrightarrow{ a } \overrightarrow{ c } \overrightarrow{ d }]+[\overrightarrow{ d } \overrightarrow{ b } \overrightarrow{ c }]\)
  3. C \([\overrightarrow{ a } \overrightarrow{ d } \overrightarrow{ b }]+[\overrightarrow{ d } \overrightarrow{ c } \overrightarrow{ a }]+[\overrightarrow{ d } \overrightarrow{ b } \overrightarrow{ c }]\)
  4. D \([\overrightarrow{ b } \overrightarrow{ c } \overrightarrow{ d }]+[\overrightarrow{ d } \overrightarrow{ a } \overrightarrow{ c }]+[\overrightarrow{ d } \overrightarrow{ b } \overrightarrow{ a }]\)
Verified Solution

Answer & Solution

Correct Answer

(A) \([\overrightarrow{ d } \overrightarrow{ c } \overrightarrow{ a }]+[\overrightarrow{ b } \overrightarrow{ d } \overrightarrow{ a }]+[\overrightarrow{ c } \overrightarrow{ d } \overrightarrow{ b }]\)

Step-by-step Solution

Detailed explanation

\(\vec{a}, \vec{b}, \vec{c}, \vec{d}\) are coplanar points. \(\vec{b}-\vec{a}, \vec{c}-\vec{a}, \vec{d}-\vec{a}\) are coplanar vectors. So, \([\overrightarrow{ b }-\overrightarrow{ a } \overrightarrow{ c }-\overrightarrow{ a } \overrightarrow{ d }-\overrightarrow{ a }]=0\)…
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