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JEE Mains · Maths · STD 12 - 11. three dimension geometry

જો સમતલો \(2 x-y+z=3,4 x-3 y+5 z+9=0\) ની છેદરેખામાંથી પસાર થતા અને રેખા \(\frac{x+1}{-2}=\frac{y+3}{4}=\frac{z-2}{5}\) ને સમાંતર સમતલનું સમીકરણ \(a x+b y+c z+6=0\) હોય, તો \(a+b+c=........\)

  1. A \(14\)
  2. B \(12\)
  3. C \(13\)
  4. D \(15\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(14\)

Step-by-step Solution

Detailed explanation

Equation of family of plane \((2 x-y+z-3)+\lambda(4 x-3 y+5 z+9)=0\) \(x(2+4 \lambda)-y(1+3 \lambda)+z(1+5 \lambda)-3+9 \lambda=0\) Parallel to the line \(-2(2+4 \lambda)-(1+3 \lambda) 4+(1+5 \lambda) 5=0\) \(5 \lambda=3\) \(\lambda=\frac{3}{5}\) equation of plane…
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