એક થેલીમાં 10 દડાઓ છે જેમાંથી k લાલ છે તથા (10 – k) કાળા છે, જ્યાં \(0 \leq k \leq 10\). જો ત્રણ દડાઓ પુરવણી રહિત યાદૃચ્છિક રીતે કાઢવામાં આવે તથા તે બધાજ કાળા માલુમ પડે છે, તો થેલીમાં 1 લાલ અને 9 કાળા દડાઓ હોવાની સંભાવના ___ છે.

A \(\frac{7}{11}\)
B \(\frac{7}{55}\)
C \(\frac{7}{110}\)
D \(\frac{14}{55}\)

Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{14}{55}\)

Step-by-step Solution

Detailed explanation

Probability \(=\frac{{ }^1 C _0 \cdot{ }^9 C _3}{\sum_{ k =0}^{10}{ }^{ k } C _0 \cdot{ }^{10- k } C _3}\) \(=\frac{{}^{9}C_{3}}{{}^{10}C_{3}+{}^{9}C_{3}+{}^{8}C_{3}+...{}^{3}C_{3}}\) \(=\frac{{}^{9}C_{3}}{{}^{11}C_{4}}=\frac{14}{55}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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વર્ગ:	\(0-10\)	\(10-20\)	\(20-30\)	\(30-40\)	\(40-50\)
આવૃતિ	\(2\)	\(3\)	\(x\)	\(5\)	\(4\)