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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

જો \(\alpha \) અને \(\beta \) એ દ્રીઘાત સમીકરણ \({x^2}\,\sin \,\theta  - x\,\left( {\sin \,\theta \cos \,\,\theta  + 1} \right) + \cos \,\theta  = 0\,\left( {0 < \theta  < {{45}^o}} \right)\) ના ઉકેલો હોય અને \(\alpha  < \beta \) તો \(\sum\limits_{n = 0}^\infty  {\left( {{\alpha ^n} + \frac{{{{\left( { - 1} \right)}^n}}}{{{\beta ^n}}}} \right)} \) = ......

  1. A \(\frac{1}{{1 - \cos \,\theta }} - \frac{1}{{1 + \sin \,\theta \,}}\)
  2. B \(\frac{1}{{1 + \cos \,\theta }} + \frac{1}{{1 - \sin \,\theta \,}}\)
  3. C \(\frac{1}{{1 - \cos \,\theta }} + \frac{1}{{1 + \sin \,\theta \,}}\)
  4. D \(\frac{1}{{1 + \cos \,\theta }} - \frac{1}{{1 - \sin \,\theta \,}}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{1}{{1 - \cos \,\theta }} + \frac{1}{{1 + \sin \,\theta \,}}\)

Step-by-step Solution

Detailed explanation

Using quadratic formula, \(x=\frac{(\cos \theta \sin \theta+1) \pm \sqrt{(\cos \theta \sin \theta+1)^{2}-4 \sin \theta \cos \theta}}{2 \sin \theta}\) \(=\frac{(\cos \theta \sin \theta+1)^{2} \pm(\cos \theta \sin \theta-1)}{2 \sin \theta}\)…
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