ExamBro
ExamBro
enEnglishhiहिन्दीguગુજરાતી
JEE Mains · Maths · STD 12 - 5. continuity and differentiation

એક વિકલનીય વિધેય \(h\) માટે, ધારોકે \(h(0)=0, h(1)=1\) અને \(h^{\prime}(0)=h^{\prime}(1)=2\). જો \(\mathrm{g}(x)=h\left(\mathrm{e}^x\right) \mathrm{e}^{h(x)}\) હોય, તો \(\mathrm{g}^{\prime}(0)\) \(=\) ..............

  1. A \(5\)
  2. B \(3\)
  3. C \(8\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(4\)

Step-by-step Solution

Detailed explanation

\( g(x)=h\left(e^x\right) \cdot e^{h(x)} \) \( g^{\prime}(x)=h\left(e^x\right) \cdot e^{h(x)} \cdot h^{\prime}(x)+e^{h(x)} h^{\prime}\left(e^x\right) \cdot e^x \) \( g^{\prime}(0)=h(1) e^{h(0)} h^{\prime}(0)+e^{h(0)} h^{\prime}(1) \) \( =2+2=4\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app